You can't use aliases you created in the SELECT clause elsewhere in the same SELECT clause, so you need to place your FIRST_VALUE() and LAST_VALUE() functions within the DATEDIFF() function:. I have a table where PurchasedDate is maintained. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. Date Part Flexibility: Years, months, days, hours, minutes, and seconds are among the date parts that are supported. Asked 11 years, 5 months ago. How to calculate days difference between two dates without leap year (365 days each year)? Thank you so much! I am new to Oracle Community Support, and I assumed that if I posted question in Oracle under SQL and PL/SQL, people would understand what I need. If you want the "exact" (as far as floating point gets) average, use. for oracle: months_between. +1 This will work for every year difference. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. cust_field_nm eq "x_case_dte_dd" and datepart. We will use the below date for the examples. 2903225806. Share. Learn more about TeamsPostgreSQL - Date Difference in Months. g. date_from, evnt. Q&A for work. Here are the 10 federal holidays a year, almost one per month: New Year’s Day on January 1; Martin Luther King’s Birthday on the. Currently I am only returning 1. (floor ( (Base_DateDiff + 0 + Start_WeekDay) / 7)) counts the number of sundays. When a user enters JAN 2009 - I want the worksheet to show data from Jan, Feb, Mar, Apr, May and June (2009). DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. DP_MONTH returns the distance between the months capturing the input dates. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. 3. 1. Converting Valid Character Strings to Dates, Times, or Timestamps. 2) format. Enter a date format string that describes the Date2 parameter. 0 months apart:Asked 3 years, 4 months ago. Step 4: Change Data Type. Modified 2 years, 6 months ago. Just divide the total by 7 to get the weeks and then calculate the remaining days. The following table lists all the valid datepart values. The days are in two different, adjacent months, so the answer is 1 month difference. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. Note that it is subtracting the second from the first, so you must have them in this order. The months_between function returns the elapsed months going from the second date to the first. Description It's easy to do date arithmetic in Oracle Database, but it can be hard to remember the formulas. So far I have this: SELECT evnt. How can we. I want to convert this number to years,Months,and Days. 000000. If you want an integer. DATE_DIFF = 1. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. . DECLARE @date datetime2 = '2021-01-07 14:36:17. 1. Date 2: 1st Feb 2011. For ex. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. I have used the below query to find the number of weeks between two dates: select count (week_id) from fw where week_begin_date >= '2015-01-01' and week_end_date <= '2015-12-31'; Expected result should be 53 but the actual result is 51. For formatting functions, refer to Section 9. If you omit fmt, then date is rounded to the. The following example illustrates how to use the. SELECT DATE '0016-08-03' - DATE '2016-07-08' FROM dual;-- -730461. You can simply subtract two dates. Also to note that: DATEDIFF. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. 0. DateAdd. Order your results by the number of years employed. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. See the valid date parts in. ExampleHere I need to calculate the difference of the two dates in the PostgreSQL. 032258 在本文中，我们介绍了oracle数据库中的datediff函数。通过指定日期部分、开始日期和结束日期，我们可以使用datediff函数计算两个日期之间的差异。这对于计算日期之间的天数、小时数、分钟数等非常有用。希望本文对您理解datediff函数的使用有所帮助。 the problem lies in the fact that a month is a nebulous thing - it is not a precise number of days. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. 6,487 5 25 37. Asked 7 years, 2 months ago. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. In Oracle, dates are just numbers. The SQL DATEDIFF() function is an in-built function in SQL that is used to return the difference (as a signed integer value) between two dates or times. Select Sysdate-Birth_date from Employees; the query return the number of days between the two dates. Oracle Fusion Global Human Resources Cloud Service - Version 11. . Currently, my code just returns zero on the right side of the decimal place. id (SELECT SUM(DATEDIFF(HOUR, a. Syntax. E. Note, that since DATEDIFF returns an integer value, the result also will be an integer. I have to get the date from the system and calculate the date difference in days. 29 Answers. 2 -Increment by 1 into total months count -. (You can also subtract fractions of days, but that might be outside the scope of this answer. 21. Current Date/Time. You've told it to compare the. Each Standard calendar week is defined to start on Sunday and it spans 7 days. The DateDiff function returns how many seconds, months, years - whatever interval you specify between the first date (here 0) and the second date (here the current date). SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is. About; Products. 365 days elapse between the two dates. HQL And datediff() Functions. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. AVERAGES CTE shows how to apply AVG function to. DateDiff function and I think it may have a parameter for indicating "in months" . For example the difference between 1st March 2011 and 3rd March 2012 is 1. Comparison with Excel DATEDIFF function. Return the current time. We would like to show you a description here but the site won’t allow us. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. date_to) * 2) - CASE WHEN DATEPART(DW, evnt. The first week of the year is 1. 8494441'. Columns c ) n cross join (select cast ('2001-01-01' as date) firstdate) const. g. I want something like this. 1 + TRUNC (InstallDate) - TRUNC (InstallDate, 'IW') get 1 for mondays to 7 for sunday. The second row is only 30 minutes apart, so the difference is 0. 1 - Find the total months count till today's date using DATEDIFF function -. Parameter Description; interval: Required. DATEDIFF. One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. , a year, a quarter, a month, a week that you want to compare between the start_date and end_date. This field level rule lets you display the difference between two dates. Asked 9 years, 3 months ago. 2903225806 DATE_DIFF =. from a date time value. type = 'P')) AS total_hour FROM a INNER JOIN ac ON ac. 510345 May 24 2006 — edited May 24 2006. 8. This is because the two dates are exactly 24 hours apart. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. I am having issues with DATE functions in SQL Plus. The following example returns 2 for the months between the two dates:. Oracle also has the TO_CHAR function, so it allows TO_CHAR(whn, 'yyyymm'), for example. Syntax. unit: The unit can be one of the following options: FRAC_SECOND (microseconds), SECOND, MINUTE, HOUR, DAY, WEEK, MONTH, QUARTER, or YEAR. I don't think this is really important to your question. Example. DP_MONTH returns the distance between the months capturing the input dates. February 28 and March 28) and when the days of the month are the last day of the month (e. 000 READDATE >= DATEADD(month, DATEDIFF(month, 0, GETDATE()) - 12, 0) -- < 2016-04-01 00:00:00. Here is my datediff function code. Use DATEADD and DATEDIFF() function together in SQL query. Right-click and select Convert to Date. Asked 5 years, 9 months ago. then the following should be the result. DATEENTERED between dateadd (mm, datediff (mm, 0, dateadd (MM, -1, getdate ())), 0) and dateadd (ms, -3, dateadd (mm,. NEW_TIME returns the date and time in time zone timezone2 when date and time in time zone timezone1 are date. The format argument is a string format that specifies which unit the date should be rounded to. I want to calculate the difference between two dates in OBIEE10g in Year/Months/Days format similar to the output of below SQL. How to calculate years of experience from date_of_hiring to till date in months of an employee using sql query. I apologize for the misinformation. この数値は、1970年1月1日の深夜から経過した秒数です。. 2258064516. The format argument is optional. getMonth (); return m2 - m1 + 1; } EDIT: Since Java 8, there is a more. 3. DATEDIFF. I thought the between operator use <= and >= so i should be getting anything on. See the following conditions: If date1 is later than date2, then the result is positive. In that case the real year difference is counted, not the rounded day difference. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. Oracle offers its own solution, although does not have the DATEDIFF function. SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. *Or even the CTIME. Again, the expected results would be a value of 1. In short. I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. Value)/30. When you multiply it by 24 (number of hours in a day), 60 (number of minutes in an hour) and 60 (number of seconds in a minute), the result is number of seconds (DIFF_SECS). 9. sql. row_number () over (partition by serialid, dateadd (dd,0, datediff (dd,0,dateadd (HH,8,createddatetime))) order by createddatetime desc) rnk. What I want to do is, given a date (say today) work out the correct Offset in the PatternDetail table for a given working pattern. . SELECT DATEDIFF(day,'2008-06-05','2008-08-05') AS DiffDate from dual is not working in SQL ERROR : ORA-00904: "DATEDIFF": invalid identifier 00904. e in the future) rather than 1992 as probably intended. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. メンバーの日. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. date_from, evnt. This post has been answered by BluShadow on Nov 18 2010. DP_QUARTER returns the distance between the quarters capturing the input dates. Taking out our calculator, we see that 30 minutes equals 1day/24hours*0. The Days, Months, and Years parameters can be negative or positive. When you subtract two dates in Oracle, you get the number of days between the two values. %DateAdd . Oracle also has its own enterprise modules and application server software. 2. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. Fractions are allowed; you can add 2. DATEDIFF SQL Server function. SELECT DATEADD(month, DATEDIFF(month, 0, @mydate), 0) AS StartOfMonth Share. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. Teams. 2188940092. 2425. COMPUTE days3 = CTIME. - Find the “date_diff” in hours and multiply it by “60”. 3. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. g. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. (floor ( (Base_DateDiff + 1 + Start_WeekDay) / 7)) counts the number of saturdays. For example, using the standard SCOTT. mm') month, 13 count(*) days 14 From calendar 15 group by to_char(datum, 'yyyy. It shows the INTER CTE. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. Returns the count (signed integer) of the specified datepart. DateDiff is use d to calculate the length of time between two dates. Click on the function name to jump to a discussion of that function. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. I know it exists in SQL Server. Here's an example. CancelDate IS NOT NULL THEN (CONVERT(NVARCHAR(MAX), DATEDIFF(day, Trips. Feb-N to Mar-N is commonly accepted as a "month". The easiest is the connect by level method: Copy code snippet. EXTRACT the number of years from the interval. 5 = 0. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. DateDiff<firstWeekDay>(Date1, Date2, Unit). Showing data 6 months greater than date parameter?? 607634 Mar 24 2010 — edited Mar 24 2010. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. SELECT datediff ( TIMESTAMP '1981-04-01 10:11:13', TIMESTAMP '2022-04-03 17:48:09') as diff FROM DUAL; Outputs: DIFF. You don't need to generate all the days as it'll be inefficient; just use a recursive sub-query factoring clause to iterate over each month: WITH months (. In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). This example returns the date of the next Sunday after January 1, 2000: SELECT NEXT_DAY ( DATE '2000-01-01', 'SUNDAY' ) FROM dual; Code language: SQL (Structured Query Language) (sql) It returns the following output: 02-JAN-00 Code language: SQL (Structured Query Language) (sql) Oracle doesn't have a DATEDIFF() function. The syntax for using the DATEDIFF function in Google BigQuery looks like the following:. SELECT AVG (DATEDIFF (d, DateUsed, DateExpires)) FROM tbl. However, The problem is different number of records because DATEDIFF(month,a,b)<=4 in SQL Server returns only the month difference whereas months_between(a,b)<=4 in oracle returns the. date. --Changing current database to the Master database allows function to be shared by everyone. TIMESTAMPDIFF ( numeric-expression string-expression. Improve this answer. So, Feb-28 to Mar-28 is a month. date_open are both of type date, you can simply subtract them to get a difference in days. startdate, SYSDATE) Keep in mind that MONTHS_BETWEEN() will return fractions of months, so use TRUNC() or ROUND() if you need an integer number. For example, suppose you have values below the start and end times. Oracle and MySQL support the SQL92 function EXTRACT, as in EXTRACT(MONTH FROM whn). first weeks into oracle. Finally, we will use a CASE statement. select trunc (months_between (:end_date,. Can be one of the following values:1 Answer. – user330315. Hi tom, I want day, month, minute and years difference everyting in seconds. T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. Write queries for continuous periods as explicit range condition. ie if the month when the query is run is march 2013. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). SELECT select AVG (months_between (SYSDATE,DOB)) AS AVERAGE_AGE_IN_MONTHS. Syntax¶ MONTHS. DATE () Extract the date part of a date or datetime expression. then just use it in the script eg. mm') 16. ) Solution 1: You can use this provided your date is in the DB datetime format Solution 2: Or Solution: You do not need to use a row generator to enumerate every day to get the number of week days - it can be done using a simple calculation: From my answer here: Difference of two DATE datatype values in Oracle represents number of days between them so. SELECT * FROM EmployeeAttendance WHERE DateJoined BETWEEN '2021-01-01' AND '2022-12-31'; This query will return all employees who joined between January 1, 2021, and December 31, 2022. subtracting date literals as pure dates without conversion. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. If you really want 'datediff' in your database, you can just do something like this: Now, i just create a view to demonstrate with: SQL> select datediff ( 'ss', d1, d2 ) seconds from temp_view; SECONDS6269539. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. , YEAR, MONTH, DAY,. In SQL Server: Like we do in SQL Server its much easier. Firstly, for example, it doesn’t really hold a date, instead it records a datetime. The dates do not have to be in the same format in the extract file, but the format of each must be supported. Kilian Hekhuis. 0. Declare @startdate datetime = '2013-11-01', @enddate datetime = '2013-11-11' SELECT (DATEDIFF (dd, @StartDate, @EndDate) + 1) - (DATEDIFF (wk, @StartDate, @EndDate) * 2) -. Beneath the plainness of its name, it hides a little depth. As you can see it means that month. However, The. Improve this answer. Commonly used datepart units include month or second. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. Asked 2 years, 9 months ago. 208333, so the value is correct! So now that we know how subtracting dates. ) Startdate = 2014-04-03 enddate = 2013-04-03 Result should be 12 as OP said. 15 between 2 values that are 1 year, 1 month and 15 days apart. 18. Viewed 20k times. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. There is no datediff in Oracle. 4 Answers. B. 0. Table 9. The system calculates the number of complete months between given dates. Then, it converts that result to a date, using the format 'yyyy-MM-dd'. But your query is giving the last date of previous month. Please note that with dates it is usually best to compare it this way: X >= lower bound AND X < upper bound. Function. 0425. If you like this article or if you have some. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. Hi Ive been having an issue with getting the correct difference in a date from the current month not including the day. I hope you will like the SQL Date Functions Examples article. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. DAYS function. This post has been answered by 630199 on Jun 1 2009. 7 months ago. The table contains the data about each staff member’s. trunc ( months_between ( end_date, start_date ) /12 ) Years, mod ( trunc ( months_between ( end_date, start_date ) ), 12 ) months, end_date - add_months (start_date,trunc ( months_between (end_date,start_date) )) days. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. Each day is 1 integer. Conversion among time units is also allowed; you can add, subtract, or compare dates by using days and state. AT TIME ZONE. candy_purchase; If purch_date has a time component, you might want to truncate the result of the date subtraction. Viewed 516 times 0 Everyone, the table relationship diagram for the database is the below one. datediff (q,start date,end date) i. However, since you have known start- and end-dates then you can find the number of full years between the two bounds and then use an INTERVAL DAY TO. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 You get the difference in days. I've tried Datediff(day, start_date, end_date), but I was prompt with: invalid column name. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. DateDiff. In MS SQL Server, the DATEDIFF function is used to get the difference between two dates in terms of years, months, days, hours, minutes etc. So, it starts with RIGHT(“00”. In SQL Server 2012 and above, you can use the EOMONTH function to return the last day of the month. ORA-00937 when calculating a sub-value in an aggregate select statement. Get the difference between datetimes in years, months, and days down to seconds. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. In Oracle, You can use the MONTHS_BETWEEN function with TRUNC and MOD function as follows: SQL> SELECT 2 TRUNC(TRUNC(MONTHS_BETWEEN(SYSDATE, DATE '2014-08. Examples of Results in Months. date_open are both of type date, you can simply subtract them to get a difference in days. Syntax %DateAdd(date_from, add_days) Description. Modified 8 years ago. That link is not for the Oracle database, it's for JavaDB (Derby). By adding the day difference to the start date, you've rounded to a whole day; select dateadd (d, 0, datediff (d, 0, getdate ())) The second method is text based: it truncates the text description with varchar (10), leaving only the date part: select convert (varchar (10),getdate (),111) The third method uses the fact that a datetime is really. A) Get the difference in months of dates on the same day The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN ( DATE '2017-07-01', DATE '2017-01-01' ) MONTH_DIFF FROM. I put a few more examples into a table and got the following results. In Calculating Work Days you can find a good article about this subject, but as you can see it is not that advanced. Table 9. SQL Server ignores that this is just one day. You can even find the number of hours, minutes, seconds, and so on in terms of details in. 1. InDays)) % (Pattern. e. Getting the 1st day of the month is simpler: select dateadd (day,- (day (current_timestamp)-1),current_timestamp) From your reference point-in-time, subtract (in days), 1 less than the current day-of-the-month component. If you subtract from one date other you will get a count of days between this two dates. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. It counts the number of year boundaries between two dates. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. If date1 is later than date2, then the result is positive. 9. The solution takes as base the first known date by SQL Server (1900-01-01). 365 / 365. Difference of two dates in months user637544 Jun 1 2009 — edited Jun 1 2009 i need to find the difference of two dates as the number of months: find the last day. getYear () * 12 + date2. Then it would also be helpful to be able to remove holidays from this. There are two methods to achieve this. Share. 9. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. Thanks in advance for any help; this has been driving us crazy for a few months now. for example, if SomeDate is 10/12/2007, that will return 12/31/2007. Current Date/Time. TASKUNIQUEID, PROJ_TASK. Étienne Miret. Returns NULL if either of <date_1> or <date_2> is NULL. The "DATEDIFF" and "Datepart" functions are used to determine years, months and days between two. dbeaver. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. If date1 and date2 are either the same days of the month or both last days of months, then the result is always. Then, we need a 2-digit month string. A) Get the next weekday later than a date. Returns a date string or the current date. Specifically, it gets the difference between 2 dates with the results returned in date units specified as years, months days, minutes, seconds as a bigint value. Kindly help on this. lastModified - w. So subtracting a TIMESTAMP WITH TIME ZONE that is 5 am Eastern from a TIMESTAMP WITH TIME ZONE that is 2 am Pacific will result in an interval of 0. MONTHS_BETWEEN: Returns an estimate of the number of months between expression1 and expression2. So, the weird number you see is the difference between the two dates. date. Get the number of months between two dates. You also wouldn't prefix a function name with the @ sign. It can be used to do date math as well. I believe you want: Select id, datediff (day, min (hire) max (hire)) as Difference From Employees group by id having count (terminated) < count (*) -- at least one NULL value. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. Given two dates then the difference between them is a number of full calendar months and the remainder is the number of days (and hours, minutes and seconds) - this is easy to find using the MONTHS_BETWEEN function and some modulo arithmetic (see my. i. Extract a value of a date time field e. SQL DATEPART. Therefore, if you’re looking for. Viewed 2k times. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. It operates according to the rules of the Gregorian calendar. Share. 2. CODE = 'CONTACT_CLIENT' THEN a. Follow edited Apr 7, 2020 at. event_id, evnt.